LeetCode-225-用栈实现队列
938b24b57e6141a29d84c66420007ea8
Implement Stack using Queues
Leetcode 225. Implement Stack using Queues
Implement the following operations of a stack using queues.
- push(x) — Push element x onto stack.
- pop() — Removes the element on top of the stack.
- top() — Get the top element.
- empty() — Return whether the stack is empty.
Example:
MyStack stack = new MyStack();
stack.push(1);
stack.push(2);
stack.top(); // returns 2
stack.pop(); // returns 2
stack.empty(); // returns false
# @Author:Kilien
# @lc app=leetcode id=225 lang=python3
# [225] Implement Stack using Queues
# time:O(1) space:O(n)
# 思路:双端队列,左进右出模拟栈
class MyStack:
def __init__(self):
"""
Initialize your data structure here.
"""
self.stack = collections.deque([])
def push(self, x: int) -> None:
"""
Push element x onto stack.
"""
self.stack.append(x)
def pop(self) -> int:
"""
Removes the element on top of the stack and returns that element.
"""
for i in range(len(self.stack) - 1):
self.stack.append(self.stack.popleft())
return self.stack.popleft()
def top(self) -> int:
"""
Get the top element.
"""
return self.stack[-1]
def empty(self) -> bool:
"""
Returns whether the stack is empty.
"""
return len(self.stack) == 0
# Your MyStack object will be instantiated and called as such:
# obj = MyStack()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.top()
# param_4 = obj.empty()
Deque定义:
Deque队列是由栈或者queue队列生成的(发音是 “deck”,”double-ended queue”的简称)。 Deque支持线程安全,内存高效添加(append)和弹出(pop),从两端都可以,两个方向的大概开销都是 O(1) 复杂度。
Deque方法:
append(x) 添加x到右端。 appendleft(x) 添加x到左端。 pop() 移去并且返回一个元素,deque最右侧的那一个。如果没有元素的话,就升起 IndexError 索引错误。 popleft() 移去并且返回一个元素,deque最左侧的那一个。如果没有元素的话,就升起 IndexError 索引错误。
>>> from collections import deque
>>> d = deque('ghi') # make a new deque with three items
>>> for elem in d: # iterate over the deque's elements
... print(elem.upper())
G
H
I
>>> d.append('j') # add a new entry to the right side
>>> d.appendleft('f') # add a new entry to the left side
>>> d # show the representation of the deque
deque(['f', 'g', 'h', 'i', 'j'])
>>> d.pop() # return and remove the rightmost item
'j'
>>> d.popleft() # return and remove the leftmost item
'f'
>>> list(d) # list the contents of the deque
['g', 'h', 'i']
>>> d[0] # peek at leftmost item
'g'
>>> d[-1] # peek at rightmost item
'i'
具体可见官方文档: collections — 容器数据类型 — Python 3.7.3 文档